Evaluating a compund expression?

Question

z=2
y=1

I have the expression:

x = y<z or z>y and y>z or z<y

Can somebody explain how this evaluates to True?

Most expressions are compound of smaller expressions. What you wanted to ask is how interleaved `and` and `or` expressions are associated when chained in a single expression, causing the minimal reproducible example of `True or True and False or False` to return `True`. So at the end this is a duplicate for https://stackoverflow.com/questions/16679272/priority-of-the-logical-operators-not-and-or-in-python — N1ngu, May 27 '22 at 12:59

score 3 · Answer 1 · answered May 27 '22 at 12:32

z=2
y=1

y<z(True) or z>y(True) and y>z(False) or z<y(False)

True OR True AND False OR False

True AND False will be evaluated first(as AND has higher precedence over OR) ;

they come out to be False

Now, True OR True AND False OR False reduces to:

True OR False OR False

So, the final output will be True

1 Answers1