for loop with unfixed number of iterations: variable naming

Question

I think I always have this problem that, whenever I want to save each output from the for loop I always implement it by giving an individual valuable for each of them.

But the question is that, sometimes the iteration of for loop is large, or sometimes the number of the valuables depends on the user input, It is a bad way to name every variable.

In my case:

for i in enumerate(actual_noises):
    if i[0] == 0:
        n1_wave, n1_sr = AudioUtil.load(i[1])
        n1_wave, n1_sr = AudioUtil.rechannel((n1_wave, n1_sr), self.channels)
        n1_wave, n1_sr = AudioUtil.resample((n1_wave, n1_sr), self.sr)
    if i[0] == 1:
        n2_wave, n2_sr = AudioUtil.load(i[1])
        n2_wave, n2_sr = AudioUtil.rechannel((n2_wave, n2_sr), self.channels)
        n2_wave, n2_sr = AudioUtil.resample((n2_wave, n2_sr), self.sr)
    if i[0] == 2:
        n3_wave, n3_sr = AudioUtil.load(i[1])
        n3_wave, n3_sr = AudioUtil.rechannel((n3_wave, n3_sr), self.channels)
        n3_wave, n3_sr = AudioUtil.resample((n3_wave, n3_sr), self.sr)

noisy_data = clean_wave + noise_1 + noise_2 + noise_3

The actual_noise is a list of k wav files:

noise type: ['/path_to/noise_1.wav', '/path_to/noise_2.wav', '/path_to/noise_3.wav']

In this case k = 3, however, I actually set it as a parameter which does not have to be fixed.

So I would like to know if there are better ways to deal with the output from the for loop.

Thanks a lot in advance! :)

@jakub thanks for the reply, but I don't think in this case will work, because I have to do further calculations to the variables — tw0930, May 30 '22 at 19:49
You don't. You have to do further calculations on *the values*, and those can be stored in lists or dicts just fine. — deceze, May 30 '22 at 20:15

for loop with unfixed number of iterations: variable naming

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