In this code, when it is run, the first part is perfect, while the second part, when I press 2, addresses an issue. I am a new coder btw

Asked May 31 '22 at 06:47

Active May 31 '22 at 06:51

Viewed 24 times

This is my code. It is a part of the main code:

        up=input("Choose your number- ")
        c = int(up)
        if type(c)==int:
            print("The number chosen is", c)
            if c%2==0:
                print(c, "is even")
            else:
                d=c+1
                print(c, "is odd, so added one to make it even")
                print (d, "is your new number")
        else:
            print("Type a number, not a word or sentence")

As we know, the input is a string. Now, when I input a number, everything is fine. But when I input a letter, it obviously brings up an error. How do I tackle this issue so that it shows no issue? I have even tried float.

edited May 31 '22 at 06:48

matszwecja

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asked May 31 '22 at 06:47

Aarav Agarwal

What do you *want* to happen if it's not an int? – matszwecja May 31 '22 at 06:49
With `c = int(up)`, `c` is guaranteed to be an `int`, so `if type(c) == int` will always be true… – deceze May 31 '22 at 06:50
as @deceze points out, your code will never reach the `else` statement, because whatever the `up` input is, it will either be converted to an integer, or it will fail and return an error when `up` can not be converted to an integer. – Mitchell van Zuylen May 31 '22 at 06:52
Ya i saw that and therefore my question – Aarav Agarwal Jun 06 '22 at 11:05

In this code, when it is run, the first part is perfect, while the second part, when I press 2, addresses an issue. I am a new coder btw

0 Answers0