Java handling exceptions functional programming

Question

I have this piece of code:

private void handleReceivedMessage(String m) throws IOException {
    switch(m) {
        case "ping":
            // code block
            ping();
            break;
        default:
            System.out.println("message not understood");
    }

}
public DataServer(int port) throws IOException {
        server = new Server(port, this::handleReceivedMessage);
        server.acceptClient();
}

now I get the error at the line this::handleReceivedMessage: Unhandled exception: java.io.IOException

How do I solve this? It's clear that the handleReceivedMessage functions does throw an IOException

Wrap it in an `UncheckedIOException` in `handleReceivedMessage` and remove the `throws IOException`? — Olivier Grégoire, May 31 '22 at 11:18
What do you exactly mean with wrapping a function with an exception? (I'm pretty new to Java) — Bilal Laaroussi, May 31 '22 at 11:23
Can you provide info about the Server class, at least about its constructor? — AddeusExMachina, May 31 '22 at 12:00

score 1 · Answer 1 · edited Jun 01 '22 at 08:48

1

Without knowing more, I'd try using a try/catch statement specifically to catch the exception being thrown as Olivier is suggesting. If may I ask, why aren't you using try/catch for error checking?

edited Jun 01 '22 at 08:48

Aniruddh Parihar

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answered May 31 '22 at 11:23

Lara Landis

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Java handling exceptions functional programming

1 Answers1