Why not to use method #2
Your second example is not recommended because if you added a new field to the Address class, then do you add it into the existing setter method or do you create a new setter method? If you add it into the existing setter method, then any classes that called that method would be broken. And if you created a new setter method, then it is confusing for anyone who wants to use that class why certain fields are grouped together that way while others are not.
Using a separate setter method for each field that you wish to expose
The common practice is to have a single setter method for each field in your class that you wish to expose (i.e. your first example). Whether or not this is a good practice is debatable because it forces a class to be mutable. It is best to make an object immutable, if possible, for a number of reasons.
Initializing your fields using a constructor
One way to make a class immutable is by getting rid of the setter methods and instead making your fields settable via your class constructor, as below. The downside to implementing it this way is that if your class has a lot of fields, it may potentially lead to large, unreadable constructor calls.
public class Address {
public String name;
public String city;
private Address(String name, String city) {
this.name = name;
this.city = city;
}
}
Initializing your fields using the Builder pattern
Below is a completely alternative implementation (inspired by this article) that is a variation of the Builder pattern. It simulates object mutability without sacrificing readability.
public class Address {
public String name;
public String city;
private Address() {}
private void setName(String name) {
this.name = name;
}
private void setCity(String city) {
this.city = city;
}
static class Builder {
private Address address = new Address();
public Builder name(String name) {
address.setName(name);
return this;
}
public Builder city(String city) {
address.setCity(city);
return this;
}
public Address build() {
return address;
}
}
}
With the above class, you could create an immutable instance of the Address class as follows:
Address address = new Address.Builder()
.name("Mansoor's address")
.city("Toronto")
.build();
Which approach uses more memory?
From a memory point of view, there shouldn't be any difference since the size of a class in memory is dependent on the fields in the class. Since all three implementations have the same fields, they should take the same amount of space in memory, regardless of which approach you use.