Javascript update variable value

Question

Ahh I really didn't want to ask, but my brain is really frying about this now.

I have a function that polls information from database API:

function fetchDatabase() {
let fetchResult = database.fetch.local(something, apiHost("api.database.com"));
return fetchResult
}

The value of fetchResult that this function gets, needs to be updated every second. So I am putting 1 second interval on the whole function:

setInterval(fetchDatabase, 1000)

Now I need to be able to access this data as a variable >>> !!! OUTSIDE !!! <<< of the function so I write:

let outsideResult = await fetchDatabase();

I then verify my code with this:

console.log(outsideResult)

I am successfully getting output of "fetchResult" every second, but the problem is, that this value does NOT update as the database API from which I'm polling the "fetchResult" gets updated.

So I am getting the same values all the time and not updated ones.

Please, how can get updated result of the API database fetch every second?

Thank you.

Please show your code in one code block. Where is this `await` done? Is it not in a loop? BTW, that `setInterval` is useless, as each time you throw away the result. — trincot, Jun 04 '22 at 14:42

score 1 · Accepted Answer · answered Jun 04 '22 at 14:45

Define your variable outside of fetch function:

function fetchDatabase()
{
  let fetchResult;
  function loop() {
    fetchResult = database.fetch.local(something, apiHost("api.database.com"));
  }
  loop();
  setInterval(loop, 1000);
  return fetchResult;
}

let outsideResult = await fetchDatabase();

Javascript update variable value

1 Answers1