Splitting strings without resulting in 2-D list

Question

How do I split strings in a list without resulting in a 2-D list?

list1:['Ben&Jerry', 'Julia', 'Sally&Don', 'Tom', 'Tracy&Jim']

to output:

['Ben','Jerry','Julia','Sally', 'Don','Tom','Tracy','Jim']

using

flat_list=[s.split('&') if "&" in s else s for s in list1 ]

will give me a 2-D list.

`[i for s in list1 for i in s.split('&')]`. Checking if delimiter is present is redundant. — Ch3steR, Jun 06 '22 at 04:55

score 6 · Answer 1 · answered Jun 06 '22 at 05:00

6

Lazy way:

flat_list = '&'.join(list1).split('&')

answered Jun 06 '22 at 05:00

Kelly Bundy

score 1 · Accepted Answer · answered Jun 06 '22 at 05:02

1

This should work

[i for j in [i.split('&') for i in list1] for i in j]

answered Jun 06 '22 at 05:02

Camilo Vera

3

See the comment by @Ch3steR for evidence that nesting a list comprehension in another is not necessary. – Chris Jun 06 '22 at 05:20

2 Answers2