It doesn't work correctly see below and how it should be
parseInt(19.31 * 100) // 1930
should be
parseInt(19.31 * 100) // 1931
Asked
Active
Viewed 28 times
0
-
4Why are you using `parseInt` at all, given you're already starting with a number? – jonrsharpe Jun 06 '22 at 15:00
-
4use `Math.round()` instead of `parseInt()`. – Barmar Jun 06 '22 at 15:00
-
parseInt rounds the number, maybe you should go for parseFloat() – Chris G Jun 06 '22 at 15:02
-
2@ChrisG — There is no point is putting a number into a function designed to turn strings into numbers. It will just implicitly convert the number to a string and then the function will convert it back. – Quentin Jun 06 '22 at 15:02
-
@ChrisG He *wants* to round the number. – Barmar Jun 06 '22 at 15:03
-
It's because `parseInt()` accepts a string. If the argument is not a string, it is converted to one using the `.toString` operation. `(19.31 * 100).toString()` is `1930.9999999999998` and if you parse that to an integer, it's `1930`. – Zsolt Meszaros Jun 06 '22 at 15:05
-
Dirty trick: `parseInt((19.31*100).toFixed(2))` – Christian Vincenzo Traina Jun 06 '22 at 15:06
-
I need this number format multiplied by 100, example: 19.31 to 1931, 19.00 to 1900 – Vadim Samoilov Jun 06 '22 at 15:07
-
Or just use `Math.round` :) – Christian Vincenzo Traina Jun 06 '22 at 15:07