Am trying to capture repeated group, for the following string.
... and abc ( xyz(d.e),'f','g','h','i',xyz('p/q'),'r') = u...
and i do expect the output to be grouped in different matches in the below format
xyz(d.e)
'f'
'g'
'h'
'i'
xyz('p/q')
'r'
The closest solution i could find was this https://stackoverflow.com/a/65244969 . So i did try with
abc\s*((?:([^,]+),?)
and got the output as
xyz(d.e)
However when i do try with
abc\s*((?:([^,]+),?)+
I get
'r') = u...
Any suggestions?
In your example strings you have either a part between single quotes or a part starting with word characters followed by parenthesis.
As your tried patterns start with abc, you might use:
(?:abc\s*\(\s*|\G(?!^),)('[^',]*'|\w+\([^()]*\))
Explanation
(?: Non capture grouop
abc\s*\(\s* Match abc a space followed by ( between optional whitepace chars| Or\G(?!^), Assert the position at the end of the previous match, but not at the start of the string to get repetitive matches. Following by matching a comma.) Close the non capture group( Capture group 1
'[^',]*' Match from '...' without matching ' or a comma in between| Or\w+\([^()]*\) Match 1+ word chars followed by (...)) Close group 1Example code getting the group 1 value:
String regex = "(?:abc\\s*\\(\\s*|\\G(?!^),)('[^',]*'|\\w+\\([^()]*\\))";
String string = "and abc ( xyz(d.e),'f','g','h','i',abc('p/q'),'r') = u";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
if (null != matcher.group(1)) {
System.out.println(matcher.group(1));
}
}
Output
xyz(d.e)
'f'
'g'
'h'
'i'
abc('p/q')
'r'
