Second function inside an if with an -And doesn't get executed (Powershell)

Question

I have the following functions

function checkA {
  Write-Host "Checking A"
  return $true
}

function checkB {
  Write-Host "Checking B"
  return $true
}

Now, in the main program I use both functions like:

if(checkA -And checkB){
  Write-Host "Checks are ok"
  return
}

I'm not getting the checkB Write-Host output and the IDE says the function is not even referenced when used like this.

Can someone tell me what's going on?

Related: [PowerShell's parsing modes: argument (command) mode vs. expression mode](https://stackoverflow.com/q/48776180/7571258) — zett42, Jun 10 '22 at 09:44

score 3 · Accepted Answer · answered Jun 10 '22 at 07:35

3

PowerShell is treating the -And as a parameter to checkA and checkB as the value of the parameter. Since checkB is not recognised as a function here, it is never called.

If you wrap the function calls in brackets, it should work as expected:

if((checkA) -And (checkB)){
  Write-Host "Checks are ok"
  return
}

answered Jun 10 '22 at 07:35

boxdog

7,894
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Yeah okey I have to take care with that. My real problem had one argument for both checkA and checkB functions so I had a bit of a mess. However wrapping it up in functions seems to work. Thanks! – andrestascon Jun 10 '22 at 07:47

Second function inside an if with an -And doesn't get executed (Powershell)

1 Answers1