how to pass a parameter to function without calling it?

Question

I have defined a two-variables function like

def f(x1, x2):
    return x1 + x2

Now, I want to pass a series of x2 into function f without calling it, to create a series of new functions. How can I achieve that?

What do you mean ‘pass into a function without calling it’? Sounds a bit like ‘how do I go swimming, without getting into the water’. Please clarify. — S3DEV, Jun 11 '22 at 12:14
Does this answer your question? [How does functools partial do what it does?](https://stackoverflow.com/questions/15331726/how-does-functools-partial-do-what-it-does) — buran, Jun 11 '22 at 12:30
Why closed? The phrase: `"create a series of new functions"` seems clear to me. There is even an answer here on that basis. — quamrana, Jun 11 '22 at 12:35
@quamrana existing close reason isn't good, but it's a dupe of [Creating Python function with partial parameters](https://stackoverflow.com/q/3258756) — SuperStormer, Jun 13 '22 at 04:10

score 2 · Answer 1 · answered Jun 11 '22 at 12:31

2

If I understand your question correctly, this sounds like a job for functools.partial:

def f(x1, x2):
    return x1 + x2

from functools import partial
funcs = [partial(f, x2=i) for i in range(10)]  # example use case

answered Jun 11 '22 at 12:31

Dominik Stańczak

1 Answers1