I'm trying to find a way to detect the plugged/unplugged event on headphone Jack in Xamarin.Android. Is there a way to do it in this? and if it is, how can I implement that functionality?
Asked
Active
Viewed 189 times
3 Answers
0
You have to write the code in xamarin.android file. Use broadcast receiver for implementation. In onReceive() you will get the intent as Intent.ACTION_HEADSET_PLUG.
Following pseudo code might help you,
public class MainActivity extends AppCompatActivity {
BroadcastReceiver broadcastReceiver;
boolean Microphone_Plugged_in = false;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
final String action = intent.getAction();
int iii;
if (Intent.ACTION_HEADSET_PLUG.equals(action)) {
iii = intent.getIntExtra("state", -1);
if (iii == 0) {
Microphone_Plugged_in = false;
Toast.makeText(getApplicationContext(), "microphone not plugged in", Toast.LENGTH_LONG).show();
}
if (iii == 1) {
Microphone_Plugged_in = true;
Toast.makeText(getApplicationContext(), "microphone plugged in",
Toast.LENGTH_LONG).show();
}
}
}
};
IntentFilter receiverFilter = new IntentFilter(Intent.ACTION_HEADSET_PLUG);
registerReceiver(broadcastReceiver, receiverFilter);
}
}

Prashant.J
- 739
- 7
- 12
-
The name '@Override' does not exist in the current context. – Vahid Ahmadi Jun 13 '22 at 06:17
-
Your solution seems to be for Java, please help with C# as well – Vahid Ahmadi Jun 13 '22 at 07:27
0
you can try to convert java code into c#, for example:
[BroadcastReceiver(Enabled = true)]
[IntentFilter(new[] { Android.Content.Intent.ActionHeadsetPlug })]
public class MyBroadcastReceiver : BroadcastReceiver
{
bool Microphone_Plugged_in = false;
public override void OnReceive(Context context, Intent intent)
{
String action = intent.Action;
int iii;
if (Intent.ActionHeadsetPlug.Equals(action))
{
iii = intent.GetIntExtra("state", -1);
if (iii == 0)
{
Microphone_Plugged_in = false;
Toast.MakeText(context, "microphone not plugged in", ToastLength.Long).Show();
}
if (iii == 1)
{
Microphone_Plugged_in = true;
Toast.MakeText(context, "microphone plugged in", ToastLength.Long).Show();
}
}
}
}
And usage:
BroadcastReceiver broadcastReceiver;
IntentFilter receiverFilter;
and initialize value in method OnCreate
of your activity:
broadcastReceiver = new MyBroadcastReceiver();
receiverFilter = new IntentFilter(Intent.ActionHeadsetPlug);
And RegisterReceiver
and UnregisterReceiver
by override method OnResume
and OnPause
protected override void OnResume()
{
base.OnResume();
RegisterReceiver(broadcastReceiver, receiverFilter);
}
protected override void OnResume()
{
base.OnResume();
IntentFilter receiverFilter = new IntentFilter(Intent.ActionHeadsetPlug);
RegisterReceiver(broadcastReceiver, receiverFilter);
}
For more, you can check thread: Detecting whether a headset is plugged into an Android device or not.
https://learn.microsoft.com/en-us/xamarin/android/app-fundamentals/broadcast-receivers

Jessie Zhang -MSFT
- 9,830
- 1
- 7
- 19
0
[BroadcastReceiver(Enabled = true)]
[IntentFilter(new[] { Android.Content.Intent.ActionHeadsetPlug })]
public class HeadsetPlugBroadcastReceiver : BroadcastReceiver
{
public override void OnReceive(Context context, Intent intent)
{
String action = intent.Action;
if (Intent.ActionHeadsetPlug.Equals(action))
{
var state = intent.GetIntExtra("state", -1);
if (state == 0)
{
// Plugged out
}
if (state == 1)
{
// Plugged in
}
}
}
}
-
`var broadcastReceiver = new HeadsetPlugBroadcastReceiver(); var receiverFilter = new IntentFilter(Intent.ActionHeadsetPlug); RegisterReceiver(broadcastReceiver, receiverFilter);` – Alexander van Meerten Jul 13 '22 at 10:57
-
1Your answer could be improved with additional supporting information. Please [edit] to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers [in the help center](/help/how-to-answer). – Community Jul 14 '22 at 00:35