I need some help to identify difference between 2 times in sec
variable :
current_time
: this is current time
check_begin_time
: in YYYYMMDDHH24MMSS format
I need to check the difference i.e. current time - check_begin_time
in secs
Thanks.
I need some help to identify difference between 2 times in sec
variable :
current_time
: this is current time
check_begin_time
: in YYYYMMDDHH24MMSS format
I need to check the difference i.e. current time - check_begin_time
in secs
Thanks.
As difference of two DATE
datatype values in Oracle represents number of days between them, you have to multiply it by 24 (as there are 24 hours in a day) and 60 (as there are 60 minutes in an hour) and 60 (as there are 60 seconds in a minute).
So:
(setting date format, just to know what is what; you don't have to do that)
SQL> alter session set nls_date_format = 'dd.mm.yyyy hh24:mi:ss';
Session altered.
I presume your value is stored as a string (according to date format you posted; though, it is wrong - minutes are MI
, not MM
) so first convert it to a DATE
datatype value, and then do the calculation:
SQL> select sysdate now,
2 (sysdate - to_date('20220614090500', 'yyyymmddhh24miss')) * 24 * 60 * 60 seconds
3 from dual;
NOW SECONDS
------------------- ----------
14.06.2022 09:09:54 294
SQL>
SELECT (END_DT - START_DT) * 60 * 60 * 24 FROM MY_TABLE; -- Seconds
SELECT (END_DT - START_DT) * 60 * 24 FROM MY_TABLE; -- Minutes
SELECT (END_DT - START_DT) * 24 FROM MY_TABLE; -- Hours
To get more info refer to this link: Date Difference