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    for key in keys.splitlines():
            
     if key == keyInput:
          request_main()    
     elif not key == keyInput:
       exit_program()

Hi, this is the code I am having trouble with; specifically line 7's else if statement, where I am getting an error for Inconsistent use of tabs and spaces in indentation. I don't see where it is inconsistent; there's no other errors elsewhere in my whole code for this. I have tried many different spacings for indentations to no avail, thank you.

Jauvo
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  • `request_main()` and `exit_program()` should have the same indentation. You can delete all the indentation in front of them, and use either space or tab to make the indentation.（and `elif not key == keyInput:` can be simplified as `else:`） – Haoliang Jun 18 '22 at 04:27
  • its because you're using `tabs` and `spaces` in the indentation, you should only use of of them – Hanna Jun 18 '22 at 04:29
  • Thank you for the solutions. Deleting all indentations and using tab to make them fixed the errors, thank you! – Jauvo Jun 18 '22 at 13:12

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