Change all occurance of password in propertie file in Bash

Question

I would like to change all password (to be encrypted) in a file, with a command and i'm stuck with my sed, i don't know how i can tell it to take the output of the sed

the example in my propeties file is like this:

someCompanie:
    username: testUsername
    password: testPassword <--- password i want to be encrypted
someOtherCompanie:
    username: testOtherUsername
    password: testOtherPassword <--- password i want to be encrypted

the result wanted is like this:

someCompanie:
    username: testUsername
    password: a2e48043fcc30e2982ed43fbab01824f1efdaf8eddcc1ac914d1815d7a8738c4 <--- password encrypted
someOtherCompanie:
    username: testOtherUsername
    password: e7c3161f3655662da261015669c3ca449b4c4a738053088b363e83ba93ebdb8f <--- password encrypted

Here's what i got:

grep "password" application.yml | cut -d ":" -f2 | xargs -I pass sed -ie 's,'"$(pass)"',test,g' "app2"

and here's my output:

sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression
sed: -e expression #1, char 0: no previous regular expression

Thanks very much for your attention,

Florian

I'm not expert enough to give you the correct command, but you should probably be able to do this with only `sed`; no need for `grep`, `cut`, or `xargs`. — Moshe Katz, Jun 19 '22 at 22:26
Please add sample input (no descriptions, no images, no links) and your desired output for that sample input to your question (no comment). — Cyrus, Jun 20 '22 at 08:39

Ed Morton · Accepted Answer · 2022-06-20T18:56:07.450

$ cat tst.sh
#!/usr/bin/env bash

encrypt() {
    printf '%s' "$1" | md5sum | cut -d' ' -f1
}

while IFS= read -r line; do
    if [[ "$line" =~ ^([[:space:]]*password:[[:space:]]*)(.*) ]]; then
        line="${BASH_REMATCH[1]}$(encrypt "${BASH_REMATCH[2]}")"
    fi
    printf '%s\n' "$line"
done < "${@:--}"

$ ./tst.sh file
someCompanie:
    username: testUsername
    password: fed3b61b26081849378080b34e693d2e
someOtherCompanie:
    username: testOtherUsername
    password: 7c0453eb71acb77f386b2798767dc97a

Replace the contents of encrypt() with a call to whatever encryption tool you want to use, called however you want to call it.

score 1 · Answer 2 · answered Jun 19 '22 at 22:40

1

Using sed, match only lines that begin with password to carry out the substitution on.

-i.bak will create a backup of the file while saving the original file in place

$ sed -i.bak '/^password/s/ .*/ newPassword/' input_file
username: testUsername
password: newPassword

answered Jun 19 '22 at 22:40

HatLess

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Thanks for the replie, but i really need some kind of loop because for each password i'm doing an encryption. That's why i thought xargs was the best solution... – Florian Frevol Jun 20 '22 at 08:31
@FlorianFrevol What kind of encryption? Do you have a tool in mind or any random password? – HatLess Jun 20 '22 at 11:04
Yes encryption with Jasypt. – Florian Frevol Jun 20 '22 at 12:10

Change all occurance of password in propertie file in Bash

2 Answers2