Problem Deserialize of XML attributes or similar with vb.net

Question

I have the following XML, but I have some problems deserializing it.

Part of XML:

<message:AIXMBasicMessage gml:id="uniqueId">
    <message:hasMember xlink:type="simple">
        <aixm:VerticalStructure gml:id="uuid.xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx">
          .....
        </aixm:VerticalStructure>
    </message:hasMember>
</message:AIXMBasicMessage>

I have these classes in VB.net

<XmlRoot(ElementName:="hasMember")>
Public Class HasMember
    <XmlElement(ElementName:="VerticalStructure")>
    Public Property VerticalStructure As VerticalStructure
    <XmlAttribute(AttributeName:="type")>
    Public Property Type As String
    <XmlText>
    Public Property Text As String
End Class

<XmlRoot(ElementName:="AIXMBasicMessage")>
Public Class AIXMBasicMessage
    <XmlElement(ElementName:="hasMember")>
    Public Property HasMember As List(Of HasMember)
End Class

<XmlRoot(ElementName:="Root")>
Public Class Root
    <XmlElement(ElementName:="AIXMBasicMessage")>
    Public Property AIXMBasicMessage As AIXMBasicMessage
    <XmlAttribute(AttributeName:="message")>
    Public Property Message As String
    <XmlAttribute(AttributeName:="xlink")>
    Public Property Xlink As String
    <XmlAttribute(AttributeName:="aixm")>
    Public Property Aixm As String
    <XmlAttribute(AttributeName:="gml")>
    Public Property Gml As String
    <XmlText>
    Public Property Text As String
End Class

the problem in message: / aixm: / xlink: / gml: because, if I delete it from the XML file it works fine. But how do I change the code, so I don't need to change the XML file to get it to be read?

This post will point you in the right direction. You need to give it the namespaces when you deserialize: https://stackoverflow.com/questions/27365029/deserializing-xml-with-namespace-and-multiple-nested-elements — Fawlty, Jun 20 '22 at 13:37
@Fawlty Thanks. I'm new to the XML deserialization and I have tried different approaches, but I cant get it to work. Also the documentation hasn't been usefull. Could I get a more precise answer? Thanks :) — jpi76, Jun 21 '22 at 08:20
Please take the time to read: https://learn.microsoft.com/en-us/dotnet/api/system.xml.serialization.xmlserializer.-ctor?view=net-6.0#system-xml-serialization-xmlserializer-ctor(system-type-system-xml-serialization-xmlrootattribute) It's important that your classes you are deserializing to match the namespaces in the XML and that you initiate the the deserializer with the correct root namespace. — Fawlty, Jun 21 '22 at 08:35
Please provide enough code so others can better understand or reproduce the problem. — Community, Jun 21 '22 at 10:00

score 0 · Answer 1 · answered Jun 21 '22 at 10:39

I got it working.

Here is the code for the classes:

<XmlRoot(ElementName:="VerticalStructure", [Namespace]:="http://www.aixm.aero/schema/5.1")>
Public Class VerticalStructure
    <XmlElement(ElementName:="identifier", [Namespace]:="http://www.opengis.net/gml/3.2")>
    Public Property Identifier As Identifier
    <XmlElement(ElementName:="timeSlice", [Namespace]:="http://www.aixm.aero/schema/5.1")>
    Public Property TimeSlice As TimeSlice
    <XmlAttribute(AttributeName:="id", [Namespace]:="http://www.opengis.net/gml/3.2")>
    Public Property Id As String
End Class

<XmlRoot(ElementName:="hasMember", [Namespace]:="http://www.aixm.aero/schema/5.1/message")>
Public Class HasMember
    <XmlElement(ElementName:="VerticalStructure", [Namespace]:="http://www.aixm.aero/schema/5.1")>
    Public Property VerticalStructure As VerticalStructure
    <XmlAttribute(AttributeName:="type", [Namespace]:="http://www.w3.org/1999/xlink")>
    Public Property Type As String
End Class

<XmlRoot(ElementName:="AIXMBasicMessage", [Namespace]:="http://www.aixm.aero/schema/5.1/message")>
Public Class AIXMBasicMessage
    <XmlElement(ElementName:="hasMember", [Namespace]:="http://www.aixm.aero/schema/5.1/message")>
    Public Property HasMember As List(Of HasMember)
    <XmlAttribute(AttributeName:="id", [Namespace]:="http://www.opengis.net/gml/3.2")>
    Public Property Id As String
    <XmlAttribute(AttributeName:="schemaLocation", [Namespace]:="http://www.w3.org/2001/XMLSchema-instance")>
    Public Property SchemaLocation As String
    <XmlAttribute(AttributeName:="gss", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Gss As String
    <XmlAttribute(AttributeName:="gts", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Gts As String
    <XmlAttribute(AttributeName:="gsr", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Gsr As String
    <XmlAttribute(AttributeName:="gml", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Gml As String
    <XmlAttribute(AttributeName:="message", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Message As String
    <XmlAttribute(AttributeName:="adr", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Adr As String
    <XmlAttribute(AttributeName:="xsi", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Xsi As String
    <XmlAttribute(AttributeName:="adfe", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Adfe As String
    <XmlAttribute(AttributeName:="aixm", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Aixm As String
    <XmlAttribute(AttributeName:="gco", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Gco As String
    <XmlAttribute(AttributeName:="ids", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Ids As String
    <XmlAttribute(AttributeName:="event", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property [Event] As String
    <XmlAttribute(AttributeName:="xlink", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Xlink As String
    <XmlAttribute(AttributeName:="gmd", [Namespace]:="http://www.w3.org/2000/xmlns/")>
    Public Property Gmd As String
End Class

As it’s currently written, your answer is unclear. Please [edit] to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers [in the help center](/help/how-to-answer). — Community, Jun 21 '22 at 14:52

Problem Deserialize of XML attributes or similar with vb.net

1 Answers1