Sorting elements in a dictionary based on the values of elements

Question

I have a dictionary in python with various numerical elements, each with a string as a key.

Example: ex_dict = {"text1" : 63 , "text2" : 71 , "text3" : 3}

I was wondering if there was a way for me to sort the elements of the dictionary based on the numerical values for each key; using a function that would output:

sorted_dict = {"text2" : 71 , "text1" : 63 , "text3" : 3}

What is the reason you want to do this? In Python 3, the default dictionary is ordered by insert order, for example. — wkl, Jun 21 '22 at 15:53
Does this answers your question: https://stackoverflow.com/questions/613183/how-do-i-sort-a-dictionary-by-value ? — Dan Constantinescu, Jun 21 '22 at 15:56

score 1 · Answer 1 · answered Jun 21 '22 at 16:01

1

can you try this?

ex_dict = {"text1" : 63 , "text2" : 71 , "text3" : 3}
{k: v for k, v in sorted(ex_dict.items(), key=lambda x: x[1], reverse=True)}

output

{'text2': 71, 'text1': 63, 'text3': 3}

answered Jun 21 '22 at 16:01

MiH

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Sorting elements in a dictionary based on the values of elements

1 Answers1