parse restful webservice xml response with javascript

Question

I want to parse the following xml which is the response from an restful webservice:

<ns2:list xmlns="urn:foo1:foo" xmlns:ns2="foo2:foo">

   <entityData>
      <namedAttributes>...</namedAttributes>
      <dynamicEnums>...</dynamicEnums>
   </entityData>

   <ns2:employees>
      <ns2:user id="test">
          <ns2:name genderTitle="0" firstName="Rock" surName="Solid"></ns2:name>
      </ns2:user >
   </ns2:employees>
</ns2:list>

If I try a xpath-expression I only get [object Object] as alert:

function parse(xml){
   var test= $(this).find('/ns2:list/ns2:employees/ns2:user[85]/ns2:name');
   alert(test);
};

Adding .text()-method like: var test= $(this).find('/ns2:list/ns2:employees/ns2:user[85]/ns2:name').text(); only makes the alert empty...

The xpath expression should not be wrong, I used Firebug to get the expression, maybe in this example some typing error.

Anyone knows whats wrong? Or the other way round: how to alert fields like firstName?

I have a very simple namespace. How I can get the value of ns2:count? 1 — Abdul Waheed, Feb 15 '19 at 17:30

Bas Slagter · Answer 1 · 2011-09-01T13:28:17.517

1

You probably need to add the namespace in your query for the name.

So you need something like:

/*[local-name()='list' and namespace-uri()='urn:foo1:foo']

edited Sep 01 '11 at 13:28

answered Sep 01 '11 at 13:21

Bas Slagter

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what do you mean? instead of ns2:...? – dotchuZ Sep 01 '11 at 13:22
Edited...maybe also googling for xpath and namespaces might help you out even more. – Bas Slagter Sep 01 '11 at 13:29

score 1 · Answer 2 · answered Sep 01 '11 at 13:27

1

Doesnt /list/employees/user[@id='test']/name/@firstName work?

answered Sep 01 '11 at 13:27

Ben

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score 0 · Accepted Answer · edited May 23 '17 at 11:55

0

you may need to look at .parseXML to parse the xml also here is a good SO answer to parse xml with namespaces jQuery XML parsing with namespaces

here is a good link too Namespace Selectors for jQuery

solution

    xmlDoc = $.parseXML(xml),
    $xml = $(xmlDoc),
    $name = $xml.find( "ns2\\:name" ).attr("surName");

   alert($name);

here id the fiddle http://jsfiddle.net/Jbnev/

edited May 23 '17 at 11:55

Community

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answered Sep 01 '11 at 13:28

Rafay

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@Vicky you must post a new question containing the necessary information – Rafay Jul 21 '13 at 18:37
@3nigma, just that jsfiddle link returns undefined. It needs to be used as a reference for future, edit that or try to remove that fiddle link. – user9371102 Jul 22 '13 at 06:18

parse restful webservice xml response with javascript

3 Answers3