python get isoformat date time from time

Question

I have this string:

date_string = "2022-04-11 00:00:00.000000"

which I'm trying to convert to this format:

date = "2022-04-11T00:00:00.000Z"

Can anyone please help me with the same

i tried to do this but am getting Error like invalid format

datetime.strptime(date_string, "%Y-%m-%dT %H:%M:%S%z")

@mkrieger1 yes i did but am getting error's like not a valid format — Newton8989, Jun 23 '22 at 12:08
yeah i'm looking for that only @mkrieger1 can you please help — Newton8989, Jun 23 '22 at 12:10
@mkrieger1 first i converted string to datetime datetime.fromisoformat(date_string) then i'm trying to convert it to datetime.strptime(date_string, "%Y-%m-%dT %H:%M:%S%z") — Newton8989, Jun 23 '22 at 12:13
please have another look at [the docs](https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior): parsing directive has to match the input ("%Y-%m-%dT %H:%M:%S%z" doesn't in your example). — FObersteiner, Jun 23 '22 at 13:01
Does this answer your question? [How do I parse an ISO 8601-formatted date?](https://stackoverflow.com/questions/127803/how-do-i-parse-an-iso-8601-formatted-date) — FObersteiner, Jun 23 '22 at 13:02

Mohit Bagadiya · Answer 1 · 2022-06-23T12:39:20.657

2

There's a library known as dateutil. With the help of that, we parse the string into date format and then we convert it into the isoformat.

import dateutil.parser as parser

date_string = "2022-04-11 00:00:00.000000"

date = parser.parse(date_string)

print(date.strftime('%Y-%m-%dT%H:%M:%SZ'))

The output would be 2022-04-11T00:00:00Z

edited Jun 23 '22 at 12:39

answered Jun 23 '22 at 12:19

Mohit Bagadiya

Hi Thank for the response but how to you add that missing Z in the end i tried to do the same but it's giving same error invalid format – Newton8989 Jun 23 '22 at 12:22
You can use this to add Z at the end of your date print(date.strftime('%Y-%m-%dT%H:%M:%SZ')) – Mohit Bagadiya Jun 23 '22 at 12:38

1 Answers1