How to create list of lists

Question

Here is what I have:

mylist = [1, 2, 7, 11, 8, 55, 89, 1, 3, 8]

How can I get this broken down by 5 to the list of lists.

The desired outcome is: [[1, 2, 7, 11, 8], [2, 7, 11, 8, 55], [7, 11, 8, 55, 89],[11, 8, 55, 89, 1], [8, 55, 89, 1, 3], [55, 89, 1, 3, 8]]

Here is what I've tried:

indices = [0,1,2]
for i in indices:
   new.append(mylist [i])
   indices = [x+1 for x in indices]
   print(indices)

Thank you in advance.

You should look at slice notation, i.e. mylist[i:i+5] should give you a slice of the list from indice `i` with length 5. You can then append this slice to an output list — David Waterworth, Jun 27 '22 at 01:30
There is no way that you tried 3 indices when you need 5 numbers. Please try and debug your programs yourself before asking. — Maarten Bodewes, Jun 27 '22 at 01:33

score 1 · Answer 1 · answered Jun 27 '22 at 01:30

1

It is easy to use a list comprehension:

>>> mylist = [1, 2, 7, 11, 8, 55, 89, 1, 3, 8]

>>> [mylist[i:i+5] for i in range(6)]
[[1, 2, 7, 11, 8], [2, 7, 11, 8, 55], [7, 11, 8, 55, 89], [11, 8, 55, 89, 1], [8, 55, 89, 1, 3], [55, 89, 1, 3, 8]]

answered Jun 27 '22 at 01:30

AboAmmar

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score 1 · Answer 2 · answered Jun 27 '22 at 01:34

The following two options are available.

List Generative

mylist = [1, 2, 7, 11, 8, 55, 89, 1, 3, 8]
res = [mylist[i:i+5] for i in range(0, len(mylist)-4)]

a loop, since it is constructed sequentially and can simply exit the loop once the length is not satisfied (see also the previous approach for a limit on the length of the loop)

mylist = [1, 2, 7, 11, 8, 55, 89, 1, 3, 8]
new = []
for i in range(0, len(mylist)):
    if len(mylist[i:i+5]) == 5:
        new.append(mylist[i:i+5])
    else:
        break

How to create list of lists

2 Answers2