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It is standard practice to continue inside a loop if a certain condition is met/unmet. In a Javascript forEach loop, this produces a syntax error:

const values = [1, 2, 3, 4, 5];
values.forEach((value) => {
    if (value === 3) { continue; }
    console.log(value);
})
SyntaxError[ ... ]: Illegal continue statement: no surrounding iteration statement

This happens whether I use function or an arrow function. How can you continue inside a forEach loop?

Obviously, you could do an inverse case (if (value !== 3) { ... }), but that is not what I'm looking for.

Chris Collett
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    Use `return` rather than `continue`. – Ouroborus Jun 27 '22 at 16:54
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    `forEach()` isn't a loop, it's a function. If you want a loop, use `for (const value of values) { … }` – robertklep Jun 27 '22 at 16:54
  • @Ouroborus `return` rather than `continue` does work correctly (+1) - it's behavior is not immediately obvious, however. It's easy to think that you are returning the parent function instead of the arrow function within the `forEach`. – Chris Collett Jun 27 '22 at 18:13

2 Answers2

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As @robertklep stated forEach() is not a loop, it is a function. You cannot use the continue keyword inside a forEach loop because its functionality is meant to loop each item in the array.

To achieve the similar behavior you can use,

  for(let item of values){
     if (item === 3) { 
      continue;
     }
     console.log(item);
  }
marc_s
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1

For practical purposes, return in a forEach() callback is equivalent to continue in a conventional for loop but it isn't the most idiomatic use of functional programming patterns

To solve that, you can filter before you loop:

const values = [1, 2, 3, 4, 5];
values.filter(v => v !== 3).forEach((value) => {
    console.log(value);
})
pastaleg
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