Subtracting date in php

Question

I'm trying to make a program that subtracts the user's inputted birthdate and the date today.

Here is my code:

$bday = $_POST['bday']; //user input 

$today=date("Y-m-d");
$myage= $today - $bday; //i got a warning message here saying "A non-numeric value encountered"

Any idea how to fix this?

`date()` returns a string, `$_POST['bday']` likely is a string as well, so neither can be subtracted — user3783243, Jun 30 '22 at 16:32

score 0 · Answer 1 · answered Jul 01 '22 at 01:07

Please try this snippet, Assuming you are requiring days and/or years as a result. I used the date_diff function for this code. Converting the user input into date/time( has the Y-m-d format) also I hard coded the user input for easier visualisation.

Working Snippet:

$input="2013-12-12"; #User input
$date = strtotime($input); #Convert user input to date time
$date1=date_create(date("Y-m-d")); #date today
$date2=date_create(date('Y-m-d', $date)); #inputted date
$diff=date_diff($date1,$date2); #date_diff function 


echo $diff->format("%Y years or %a days");

Output:

8 years or 3123 days

There is possibly a cleaner version of this. But I believe this is the right flow for your requirements.

Subtracting date in php

1 Answers1