According to another answer, it seems yes, but it looks like any binary counter implementation uses some kind of "clock".
So, is NAND/NOR still turing complete without "clock" component?
According to another answer, it seems yes, but it looks like any binary counter implementation uses some kind of "clock".
So, is NAND/NOR still turing complete without "clock" component?
For an overview of the topic, this related post is helpful.
A combinational logic circuit composed of NAND
and NOR
gates without feedback loops is not a Turing complete machine. It lacks memory and it cannot execute a program with loops and conditional branches. The output values only depend on the current input values. Disregarding transient signal changes, such a circuit exhibits a purely static behaviour.
However, SR flip flops as basic elements of sequential logic can be built out of NAND
gates. Additional combinational logic determines, how the state machine transitions from one state to the other. Such a finite state machine is still not Turing complete, as it has a finite amount of memory. See this related post.
So, an infinite NAND
/NOR
circuit could be a candidate to analyze for Turing completeness.