Regex Match phrases with or without quotation

Question

im new to regular expressions and i want to build an expression that finds the below pattern:

We have the string:

"'Hello world',dude, 'Somethings, never, turn and go', bye"

I want a regular expression that gives this result:

['Hello world',dude,'Somethings, never, turn and go',bye]

Basically, splitting the string on comma but keeping the phrases with quotes that have comma as a whole.

I tried this ('\s*,\s*') but doesnt work.

Use `eval(s.replace(/^/, "\[").replace(/$/, "]"))` but before that you shoud have declared `dude` and `bye` — Artyom Vancyan, Jul 08 '22 at 12:11
@ArtyomVancyan Wait i might not have been clear enough. I want to give as a result an array not a string with brackets. Basically, splitting the string on comma but keeping the phrases with quotes that have comma as a whole. — Nick, Jul 08 '22 at 12:17

score 2 · Answer 1 · answered Jul 08 '22 at 12:27

2

I think you want something like:

const regex = /(?:\'.*?\')|(?:\w+)/g;

const str = "'Hello world',dude, 'Somethings, never, turn and go', bye";

console.log(str.match(regex));

answered Jul 08 '22 at 12:27

Alan Friedman

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You can omit the non capture groups here `(?:` You can write it as `'[^'\n]*'|\w+` – The fourth bird Jul 08 '22 at 12:32
This will get more complicated if there can be escape sequences inside the single quoted strings. Nad even more if there can be escape sequences outside of single quoted strings. – Wiktor Stribiżew Jul 08 '22 at 12:41
This wont work for the case 'Hello world's' – Nick Jul 08 '22 at 13:29

JvdV · Answer 2 · 2022-07-08T12:29:42.100

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Maybe try (?<=')\s*,\s*|\s*,\s*(?=')

let s = "'Hello world',dude, 'Somethings, never, turn and go', bye";
let arr = s.split(new RegExp(String.raw`(?<=')\s*,\s*|\s*,\s*(?=')`, 'g'));
console.log(arr)

edited Jul 08 '22 at 12:29

answered Jul 08 '22 at 12:22

JvdV

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"dude, 'Somethings, never, turn and go'", are not splitted. Also the positive lookbehind may not be supported in all browsers – Nick Jul 08 '22 at 12:24
Yeah just noticed. Let me rework this. @Nick – JvdV Jul 08 '22 at 12:25
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You can also use a literal in this case as you are not dynamically creating a regex `let arr = s.split(/(?<=')\s*,\s*|\s*,\s*(?=')/);` – The fourth bird Jul 08 '22 at 12:40
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Right, even better! I'll leave my answer as is, and you keep the comment down to add value @Thefourthbird. – JvdV Jul 08 '22 at 12:47
the positive lookbehind may not be supported in all browsers – Nick Jul 08 '22 at 13:40
@JvdV if i add this string "'Hello world',dude, Somethings, never, turn and go, bye" it gives this result ["'Hello world'", 'dude, Somethings, never, turn and go, bye'] which is wrong. It doesnt split the other values separated by comma – Nick Jul 08 '22 at 23:05

Regex Match phrases with or without quotation

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