Is there a shorter way of doing this in python?

Question

Is there a shorter way to perform an operation on each dictionary item, returning a new dictionary without having to first create an empty dictionary like i did? Note: The original a_dictionary values should not be changed.

a_dictionary = {'one': 1, 'two': 2, 'three': 3, 'four': 4}
result_dict = {}
result_dict.update((x, y*2) for x, y in a_dictionary.items())

Yes, the generator expression can be passed directly to `dict`. — chepner, Jul 08 '22 at 13:52
A dict comprehension is more readable if you are *constructing* the key/value pairs, but I would prefer `dict(some_iterable)` over `{k: v for k, v in some_iterable}`. — chepner, Jul 08 '22 at 13:55
@chepner Trying to use `dict(some_iterable)`, This is the best i can think of `result_dict = dict(zip(a_dictionary.keys(), [x*2 for x in a_dictionary.values()]))`. — BaRzz007, Jul 13 '22 at 02:01
You already have the generator expression you want being passed to `result_dict.update`. Just pass it to `dict` instead: `result_dict = dict(...)`. — chepner, Jul 13 '22 at 11:42

score 2 · Accepted Answer · edited Jul 08 '22 at 14:03

2

You can use dict comprehension:

result_dict = {x: y*2 for x, y in a_dictionary.items()}

edited Jul 08 '22 at 14:03

Jesper

202,709
46
318
350

answered Jul 08 '22 at 13:52

bereal

32,519
6
58
104

Is there a shorter way of doing this in python?

1 Answers1