How to get an image from an API response with content type "mime: image/jpg" in Python?

Question

I did a request to an API and obtain characters from an image. I want to put those characters into a 'jpg' file to be able to visualize the image. The content-type is 'mime: image/jpg' and the data is the following one (it's not the complete one because it would be too much):

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

How can I do it?

score 3 · Accepted Answer · answered Jul 14 '22 at 16:47

A quick bit of research indicates /9j/ is a magic number likely indicating the binary representation of a JPEG file that's been Base64-encoded. (Source).

Thus it should be possible to use the base64 module in Python to generate the file you describe:

import base64
jpg_b64_string_data = "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"
image_data = base64.decodestring(jpg_b64_string_data)
f = open("image.jpg", "w")
f.write(image_data)
f.close()

How to get an image from an API response with content type "mime: image/jpg" in Python?

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