Javascript hoisting with variable and function

Question

var a=2;
function a(){};
console.log(typeof(a));

I am wondering why the result of the above code is number. I know the var is hoisted but isn't it already at the first line of the code? so why the type of a is still a number instead of a function?

`function` is hoisted above `var` and then you redeclare it as a number — pilchard, Jul 14 '22 at 21:41

score 2 · Accepted Answer · answered Jul 14 '22 at 21:40

2

In this case function a(){} is actually hoisted, which you can see if you log a at various points:

console.log(a);
var a = 2;
console.log(a);
function a() {
    console.log('hi');
}


console.log(a);

answered Jul 14 '22 at 21:40

dave

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Javascript hoisting with variable and function

1 Answers1