How to take the select word from python code and printing in script shell after calling the script from python?

Question

I have the code python

import os
# put the words you want to match into a list
matching_words = ["apple", "pear", "car", "house"]

# get some text from the user 
user_string = input("Please enter some text:")

# loop over each word in matching_words and check if it is a substring of user_string
for word in matching_words:
    if word in user_string:
        print("\n{} is in the user string\n\n".format(word))
        os.system('/home/raed/Desktop/1.sh')

And I have this code in script

#! /bin/bash
########################
if [ "$2" = "pear" ]; then
    echo " This is '$2'"
elif [ "$2" = "apple" ]; then
    echo " This is '$2'"
else
    echo " This is '$2'"
exit 0

So If I choose any word from list of python code I need the script recognize and print it

I have got this error How to solve it ?!!

Please enter some text:apple

apple is in the user string


/home/raed/Desktop/1.sh: line 10: syntax error: unexpected end of file

does the file /home/Desktop/1.sh exist? you are not passing any param to your script — bpfrd, Jul 15 '22 at 14:31
the problem is in your bashscript you expect to get parameters (because of $2) but you don't give any param to your script — bpfrd, Jul 15 '22 at 14:51

score 1 · Accepted Answer · answered Jul 15 '22 at 16:04

You need to include your word as an argument in your python program.

Following is a snippet of code with some minor revisions to your program.

import os
# put the words you want to match into a list
matching_words = ["apple", "pear", "car", "house"]

# get some text from the user 
user_string = input("Please enter some text:")

# loop over each word in matching_words and check if it is a substring of user_string
for word in matching_words:
    if word in user_string:
        com = '/home/craig/Python_Programs/Script/1.sh ' + word
        print("\n{} is in the user string\n\n".format(word))
        os.system(com)

Also, in your bash script, you will want to check argument #1 ($1) in lieu of argument #2 ($2) as noted in the following tweaks to your script.

#! /bin/bash
########################
if [ "$1" = "pear" ]; then
    echo " This is '$1'"
elif [ "$1" = "apple" ]; then
    echo " This is '$1'"
else
    echo " This is '$1'"
exit 0

fi

Following is a sample of the output from my terminal.

Una:~/Python_Programs/Script$ python3 Script.py 
Please enter some text:apple

apple is in the user string


 This is 'apple'
Una:~/Python_Programs/Script$ python3 Script.py 
Please enter some text:pear

pear is in the user string


 This is 'pear'

I believe that will net you the results you are after.

Regards,

How to take the select word from python code and printing in script shell after calling the script from python?

1 Answers1