Hourly Time Series Analysis on r in Hydrology

Question

I am trying to separate the events from streamflow data. I have hourly data. I have run the code

dailyMQ <- data.frame(Date=seq(from=as.Date("01.01.2000", format="%d.%m.%Y"), 
to=as.Date("01.01.2004", format="%d.%m.%Y"), by="days"), 
discharge=rbeta(1462,2,20)*100)

for daily data. But I am trying for hourly data but getting errors. Could anyone suggest me how to write a code for hourly data?

Thanks

HourlyMQ <- data.frame(Date=seq(from=as.Date("01.01.2019", format="%d.%m.%Y"), to=as.Date("11.12.2019", format="%d.%m.%Y"),by="hours"),discharge=rbeta(8274,2,20)) — Manpreet Kaur, Jul 19 '22 at 18:09

score 0 · Answer 1 · answered Jul 20 '22 at 05:19

0

Date format can't directly be split into hours.

You could use POSIXct datetime format:

HourlyMQ <- data.frame(Date=seq(from=as.POSIXct("01.01.2019", format="%d.%m.%Y"), to=as.POSIXct("11.12.2019", format="%d.%m.%Y"),by="hours"),discharge=rbeta(8257,2,20)) 
HourlyMQ
#>                     Date    discharge
#> 1    2019-01-01 00:00:00 0.2452214482
#> 2    2019-01-01 01:00:00 0.0620291334
#> 3    2019-01-01 02:00:00 0.0608788870
#> 4    2019-01-01 03:00:00 0.0697449808
#> 5    2019-01-01 04:00:00 0.0302780135

answered Jul 20 '22 at 05:19

Waldi

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but There is a problem – Manpreet Kaur Jul 21 '22 at 16:05
Date Hours Discharge 20190101 0:00 0.1639 20190101 1:00 0.1639 20190101 2:00 0.1739 20190101 3:00 0.182 20190101 4:00 0.1887 20190101 5:00 0.1941 20190101 6:00 0.1991 20190101 7:00 0.2013 20190101 8:00 0.2015 20190101 9:00 0.1991 20190101 10:00 0.1947 20190101 11:00 0.1914 20190101 12:00 0.17 20190101 13:00 0.1839 but in R – Manpreet Kaur Jul 21 '22 at 16:07
When we run this command then our HourlyMQ comes out to be – Manpreet Kaur Jul 21 '22 at 16:08
for discharge, 0:00 - 0.0666, 1:00 - 0.1266, 2:00 - 0.1179, 3:00 - 0.1624 – Manpreet Kaur Jul 21 '22 at 16:12
Could you edit your question with a [minimal reproducible example](https://stackoverflow.com/a/5963610/13513328)? – Waldi Jul 21 '22 at 17:54
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Hi, I solved this problem. Thank you so much for the guidance. I will reach out to you whenever I got stuck. – Manpreet Kaur Jul 22 '22 at 14:46
Hi, Could you please help me to find "Run_WebFlood()" command? – Manpreet Kaur Aug 03 '22 at 23:19
Is this what you're looking for? https://rdrr.io/github/PhilippBuehler/FloodR/man/Run_WebFlood.html – Waldi Aug 04 '22 at 04:17
Yes yes, but could not able to run RunFlood command – Manpreet Kaur Aug 11 '22 at 19:34

Hourly Time Series Analysis on r in Hydrology

1 Answers1