how to declare resources based on command line argument in python?

Question

I am trying to test my code in different environments, test , prod ... I am planning to create a .env file and setting values for test and prod. but i have some declarations, line number 2 in sample below. i only need that when i run in local machine. how can i pass on an argument via command line, say main.py local and only then it executes at line else ignores it.

main.py

#connect to our cluster
1. from elasticsearch import Elasticsearch

#local mode only
2. ec2 = boto3.Session(profile_name='dev', region_name='eu-west-1').client('ec2')


if __name__ = "__main__"

check out `sys.argv` inside the `sys` module – TheLazyScripter Jul 20 '22 at 02:22 — TheLazyScripter, Jul 20 '22 at 02:22

score 1 · Accepted Answer · answered Jul 20 '22 at 02:39

1

You can use the sys library and sys.args like this:

import sys

x = sys.argv[1]
print(x)

use sys.argv[1] not 0 because 0 is actually the filename

answered Jul 20 '22 at 02:39

The Peeps191

153
1
8

thanks . I guess, we can check for this outside a python function too, right? like at the very top of the file? – ozil Jul 20 '22 at 22:10
yea, it doesn't change (the values of sys.argv) – The Peeps191 Jul 21 '22 at 21:10

how to declare resources based on command line argument in python?

1 Answers1