change the order of numbers from the back

Question

they need to order with a problem

so I have the text in a certain order of numbers, something like gematria

input [12345] is what we call gematria and what do they need?

they need to line up the digits backwards

[54321] have a different count and I would need help with that rather than doing twenty different if

def shiftall(s, n):
     n %= len(s)
     return s[n:] + s[:n]

it didn't help me much it only moves the simple text

Does this answer your question? [How to reverse a list?](https://stackoverflow.com/questions/3940128/how-to-reverse-a-list) — NelsonGon, Jul 22 '22 at 19:13
The function you showed is for rotating a list, not reversing it. — Barmar, Jul 22 '22 at 19:14
You can read the answers on the duplicate post and if they work mark this as duplicate. — NelsonGon, Jul 22 '22 at 19:16

Ryan · Accepted Answer · 2022-07-22T19:17:53.303

1

For strings:

return s[::-1]

For integers:

return str(s)[::-1]

Note: This would go inside def shiftall(s, n): Additional note: Now you don't even need the parameter n

edited Jul 22 '22 at 19:17

answered Jul 22 '22 at 19:16

Ryan

1

`test = "1234" print(test[::-1])` yes thanx :D it didn't occur to me that it could also work with whole numbers, I learned something new again, thank you – Nobikk Jul 22 '22 at 19:20

score 0 · Answer 2 · answered Jul 22 '22 at 19:17

0

If you want to reverse a number, then you can convert it to a string, reverse the string, and then convert it back to a number.

num = 12345
str_num = str(num)
# reverse and convert
num = int(str_num[::-1])

answered Jul 22 '22 at 19:17

The Peeps191

Nurtazim Bakytov · Answer 3 · 2022-07-22T19:57:08.697

-1

input=[12345,43545436,88888,843546]

def shiftall(s):            
d=[]
for i in s:

    res=''.join(reversed(str(i)))

    d.append(int(res))

return d

print(shiftall(input))

edited Jul 22 '22 at 19:57

answered Jul 22 '22 at 19:54

Nurtazim Bakytov

3 Answers3