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Here is my if statement

if (
      currentPosition.id.includes("a") ||
      currentPosition.id.includes("b") ||
      currentPosition.id.includes("c") ||
      currentPosition.id.includes("d") ||
      currentPosition.id.includes("e") ||
      currentPosition.id.includes("f") ||
      currentPosition.id.includes("g")
    ) {}

Is there a more efficient way to do this?

AlexTWO
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  • 6
  • `function isPositionIncludes(str) {return currentPosition.id.includes(str)}` – NNL993 Jul 25 '22 at 09:52
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    If you want to alphabet range then, use `/[a-g]/.test(currentPosition.id)`. If it is any substring, then `/a|b|c|d|e|f|g/.test(currentPosition.id)` Separate each substring with a `|` – adiga Jul 25 '22 at 09:55

0 Answers0