Choose one random part of loop

Question

a = 1
b = 2 

for i in range():
    print(a)
    #print(b)

I am trying to make a code. How can I make that randomly in one part of loop it will print b. For example one it will print "112111" and next time "211111".

Did you mean the loop should print `b` just once? – quamrana Jul 25 '22 at 16:09 — quamrana, Jul 25 '22 at 16:09

Fra93 · Answer 1 · 2022-07-25T16:28:08.197

1

From the context of your question you want to print b only once.

import random

a = 1
b = 2

import random
b_index = random.randint(0,3)

res = [ a if i != b_index else b for i in range(4) ]
print(res)

edited Jul 25 '22 at 16:28

answered Jul 25 '22 at 16:12

Fra93

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b_is_printed is not used – Ben Jones Jul 25 '22 at 16:25
1

The code works though, I removed it. I don't think it deserves a downvote. – Fra93 Jul 25 '22 at 16:28

score 1 · Answer 2 · answered Jul 25 '22 at 16:12

Maybe not the most elegant solution but this should work. You assign at which index should B be printed at random and run the loop as below:

import random

A = 1
B = 2
LEN = 6
PRINT_B_INDEX = random.randint(0, LEN-1)

def main():
    for i in range(LEN):
        if i == PRINT_B_INDEX:
            print(B)
        else:
            print(A)

if __name__ == "__main__":
    main()

Michael Ruth · Answer 3 · 2022-07-25T16:16:39.403

0

Use the random module. One possible solution is random.shuffle(), which will shuffle the elements of s. This does not require a for loop.

import random
s = ["1", "1", "1", "1", "2"]
random.shuffle(s)
print("".join(s))

edited Jul 25 '22 at 16:16

answered Jul 25 '22 at 16:07

Michael Ruth

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And if I want to be sure that "2" will be printed only once? – Marcin Sochacki Jul 25 '22 at 16:10
4

Then you need to state that more explicitly in your question. Will update my solution. – Michael Ruth Jul 25 '22 at 16:11

Choose one random part of loop

3 Answers3