What is the simplest way to use 'not in' kind operator

Question

I have 2 list

A=['1','2','3','4','5','6','7','8','t','e','e','e','r','t',','w','w',','r','r']

B=['5','6','7','8','t','e','e','e','r','t',','w','w',','r','r','d','f','w','w','r','r]

I have to extract all elements of A which is not present in B

I am trying

final=[]
for i in A:
   for j in B:
      if i!= j :
        final.append(i)

still i am not getting what i want

You should use sets if you are not keen on order – sammywemmy Jul 26 '22 at 05:26 — sammywemmy, Jul 26 '22 at 05:26
You already know you want `not in`… `if i not in B`. – deceze Jul 26 '22 at 05:28 — deceze, Jul 26 '22 at 05:28

score 3 · Answer 1 · answered Jul 26 '22 at 05:26

3

final = [i for i in A if i not in B]

Or, if not order nor duplicates are important to preserve:

final = set(A) - set(B)

answered Jul 26 '22 at 05:26

shx2

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score 0 · Answer 2 · answered Jul 26 '22 at 05:35

0

You could turn them into type set

A = set(A)
B = set(B)
print(A.difference(B))

>>> {'1', '3', '4', '2'}

more info here

answered Jul 26 '22 at 05:35

LrnzDC3696

1

What is the simplest way to use 'not in' kind operator

2 Answers2