Run variable containing variables (with space) as a command on Linux/bash

Asked Jul 27 '22 at 10:02

Active Jul 27 '22 at 10:02

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I'm trying to run a variable as a command on Linux. But this variable also has variables inside. Basically, I have the following:

CMAKE=cmake
GENERATOR="Unix Makefiles"
CMAKE_CONFIGURE_="$CMAKE -G \"$GENERATOR\""

when I echo it, it seems that I have what I want:

cmake -G "Unix Makefiles"

However, when I try to run CMAKE_CONFIGURE_ as a command like so:

$CMAKE_CONFIGURE_

I have the following error:

CMake Error: Could not create named generator "Unix

It seems the string $GENERATOR is passed as two arguments because of the space. How could I solve this issue?

asked Jul 27 '22 at 10:02

laultimapregunta

Try executing your command like this `"$CMAKE_CONFIGURE_"` – Yannis Sauzeau Jul 27 '22 at 10:06
1

https://stackoverflow.com/questions/66681848/bash-storing-a-command-in-a-variable-cmd-and-then-running-it-with-cmd-fails https://unix.stackexchange.com/questions/444946/how-can-we-run-a-command-stored-in-a-variable – KamilCuk Jul 27 '22 at 10:09
@KamilCuk thanks for the second link, eval did the trick! – laultimapregunta Jul 27 '22 at 15:31

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