How to display Contacts in alphabetic order in Listview

Question

I have a custom List view and i need to display the contacts in Alphabetical order can u provide the sample code how can i achieve this?

score 41 · Answer 1 · edited May 23 '17 at 12:16

you can get contacts in alphabatical order like this:

Cursor cursor = getContentResolver.query(Phone.CONTENT_URI, null, null, null, Phone.DISPLAY_NAME + " ASC");

refer these links for more cearity:

How to call Android contacts list?

How to get contacts from native phonebook in android

How to obtain all details of a contact in Android

How to get the first name and last name from Android contacts?

How to import contacts from phonebook to our application

Android contacts extraction

How to get all android contacts but without those which are on SIM

For list you can refer this tutorial:

http://www.vogella.de/articles/AndroidListView/article.html

score 2 · Answer 2 · edited Sep 14 '17 at 11:57

2

You need to do this:

Cursor cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC");

edited Sep 14 '17 at 11:57

Gourav Joshi

2,419
2
27
45

answered Sep 14 '17 at 11:36

N.Zyzek

21
3

Thanks. I wonder why the question owner didn't accept it – CodeSlayer May 11 '18 at 17:42

Zar E Ahmer · Answer 3 · 2016-07-13T07:02:48.567

I have added Alphabetic headers to contact list

new ReadContactTask(context, showProgressDialog,new OnContactReadListener() {
            @Override
            public void onContactRead(List<ContactItem> dummyList) {

                ArrayList<ContactItem> latestPhoneContacts = new ArrayList<>();

                if(dummyList!=null && dummyList.size()>0)
                {
                    tvNoResult.setVisibility(View.GONE);

                    for(ContactItem contactItem : dummyList){
                        String contactNameInCapital = "";
                        if(contactItem.getContactName()!=null && contactItem.getContactName().length()>2){
                            contactNameInCapital = contactItem.getContactName().substring(0,1).toUpperCase();

                            if(contactNameInCapital.charAt(0) != previousContact.charAt(0))
                            {
                                latestPhoneContacts.add(new ContactItem(contactNameInCapital.substring(0,1)));
                                latestPhoneContacts.add(contactItem);
                            }
                            else
                            {
                                latestPhoneContacts.add(contactItem);
                            }

                            previousContact = contactNameInCapital;
                        }
                    }
                    if(latestPhoneContacts!=null && latestPhoneContacts.size()>0)
                        contactListAdapter.addItems(latestPhoneContacts);
                }
            }

            @Override
            public void onContactEmpty() {

            }
        }).execute();

where

private String previousContact ="Zee";

score 0 · Answer 4 · answered Sep 06 '11 at 09:02

use this code to retrieve the contacts

ArrayList<HashMap<String,String>> contactData=new ArrayList<HashMap<String,String>>();
ContentResolver cr = getContentResolver();
     Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
     while (cursor.moveToNext()) {
         try{
         String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID)); 
         String name=cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
         String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); 
         if (Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
             Cursor phones = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId, null, null);
             while (phones.moveToNext()) { 
                 String phoneNumber = phones.getString(phones.getColumnIndex( ContactsContract.CommonDataKinds.Phone.NUMBER));
                 HashMap<String,String> map=new HashMap<String,String>();
                 map.put("name", name);
                 map.put("number", phoneNumber);
                 contactData.add(map);
             } 
             phones.close(); 
         }
     }catch(Exception e){}
     }

Now the contact details are stored in the contactData ArrayList. Now sort this arrayList like bellow

Collections.sort(contactData, new Comparator(){
                @Override
                public int compare(Object o1, Object o2) {
                    HashMap map1=(HashMap)o1;
                    HashMap map2=(HashMap)o2;
                    String s1=(String)map1.get("name");
                    String s2=(String)map2.get("name");
                    return s1.compareTo(s2);
                }
            });

Now the contact details are stored in the sorting order in the contactData ArrayList.

This worked , but there are duplicates in each contact – Jack Dec 08 '17 at 09:48 — Jack, Dec 08 '17 at 09:48

How to display Contacts in alphabetic order in Listview

4 Answers4

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