How to remove elements from array if not matching?

Question

I am trying to delete all elements that matches @b.com, but it returns an empty array even if I remove the !, which leads me to think, I am doing something competently wrong.

Can someone explain what I am doing wrong?

    const arr = ['a@a.com', 'b@b.com', 'c@c.com'];
    
    if (arr !== null && arr.length > 0) {
       const arr2 = arr.filter(e => {
          !e.match(/@b.com/);
       });
       console.log(arr2);
    }

Does this answer your question? [Curly Brackets in Arrow Functions](https://stackoverflow.com/questions/35440265/curly-brackets-in-arrow-functions) — Thomas, Aug 04 '22 at 07:22

score 2 · Accepted Answer · answered Aug 04 '22 at 07:23

You forgot return statement:

const arr = ['a@a.com', 'b@b.com', 'c@c.com'];

if (arr !== null && arr.length > 0) {
   const arr2 = arr.filter(e => {
      return !e.match(/@b.com/);
   });
   console.log(arr2);
}

One more thing, if you don't match by regex, you can just use string.includes:

const arr = ['a@a.com', 'b@b.com', 'c@c.com'];

if (arr !== null && arr.length > 0) {
   const arr2 = arr.filter(e => {
      return !e.includes('@b.com');
   });
   console.log(arr2);
}

score 0 · Answer 2 · answered Aug 04 '22 at 07:46

0

You forget the return statement.

const arr = ['a@a.com', 'b@b.com', 'c@c.com'];
const arr2 = arr?.length ? arr.filter((e) => !e.match(/@b.com/)) : [];
console.log(arr2);

answered Aug 04 '22 at 07:46

Meer Humza

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How to remove elements from array if not matching?

2 Answers2