Regex pattern with accented characters

Question

I am trying to get the words that start with a capital letter regardless of whether it has a special character or not in the word. Currently, my pattern only gets capital letters without accents.

I don't need numbers or hyphens, just accents or special characters in the letters.

pattern = r"\b[A-Z][a-z]*\b"
name = soup.select('h1.data-header__headline-wrapper')[0].text.strip()
name = re.findall(pattern, name)
name = " ".join(name)

Some examples. Special characters should be included to correctly return player 1 and 4.

�lvaro Fern�ndez
[]

#3                    
                                            Rico Henry
['Rico', 'Henry']
Rico Henry
#24                    
                                            Tariqe Fosu
['Tariqe', 'Fosu']
Tariqe Fosu
#29                    
                                            Mads Bech S�rensen
['Mads', 'Bech']
Mads Bech

Answer 1

You need to pip install regex in your console and then use

import regex
pattern = r"\b\p{Lu}\p{Ll}*\b"
name = soup.select('h1.data-header__headline-wrapper')[0].text.strip()
name = regex.findall(pattern, name)
name = " ".join(name)

Here,

• \b - a word boundary
• \p{Lu} - an uppercase letter
• \p{Ll}* - zero or more lowercase letters.

If you cannot install the PyPi regex module you need to build ranges of upper- and lowercase letters (based on Python regex for unicode capitalized words):

import sys, re
pLu = '[{}]'.format("".join([chr(i) for i in range(sys.maxunicode) if chr(i).isupper()]))
pLl = '[{}]'.format("".join([chr(i) for i in range(sys.maxunicode) if chr(i).islower()]))
pattern = fr"\b{pLu}{pLl}*\b"
name = soup.select('h1.data-header__headline-wrapper')[0].text.strip()
print ( " ".join( regex.findall(pattern, name) ) )

See this Python demo.