Is Inequality Transitive in Java?

Question

If I have 3 objects a, b, and c, and I want to check that none of them are equal to each other, I need to check:

if (!a.equals(b) && !b.equals(c) && !a.equals(c)) { // to simplify, assume non-null
    // do something
}

According to the Java docs, for a correctly implemented equals method:

It is transitive: for any non-null reference values x, y, and z, if x.equals(y) returns true and y.equals(z) returns true, then x.equals(z) should return true.

This states that equality is transitive, but what about inequality?

Answer 1

It's not transitive. Consider x=1, y=2 and z=1.

Answer 2

Inequality is never transitive (if you have 2 elements that are not equal, a and b). Because then you have !a.equals(b) and, because of symmetry !b.equals(a), but because of identitiy you have a.equals(a). So unequality cannot be transitive.

Answer 3

given a = 5; b = 6; c = 5:

a != b -> true

b != c -> true

a != c -> false

so no, inequality is not transitive.

Answer 4

No, of course not.

2 != 3
3 != 2

but

2 == 2

Answer 5

Well, no. For transitivity you need the condition true for any x, y, z; but if I pick z == x, I would very much hope that

x != y

and y != z

does NOT then imply

x != z

since z is x!