Bash Error when echo print two number variables

Asked Aug 12 '22 at 20:12

Active Aug 12 '22 at 20:23

Viewed 21 times

Look at this folks

r1=$(grep -c "Error_type1" file.txt)

r2=$(grep -c "Error_type2" file.txt)

all fine until here, but if I try to print total of errors:

echo $r1+$r2

$1+1

echo $(r1+r2)

$command not found

echo $($r1+$r2)

$command not found

I don´t wanna create a 3rd variable with the sum. Any ideas?

edited Aug 12 '22 at 20:23

Cyrus

asked Aug 12 '22 at 20:12

user2464460

2

You want `$((r1+r2))`. `$(...)` is for executing a command and substituting its output, `$((...))` executes arithmetic. – Barmar Aug 12 '22 at 20:14
You obviously already know that, since you use `$(grep ...)` – Barmar Aug 12 '22 at 20:15

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