How to assert a list in which each value should be one the values of the expected list?

Question

I am trying to assert a list using match contains any, match each but it is not working.

def actualList = ["CABLE_MODEM","SET_TOP_BOX","SET_TOP_BOX","CABLE_MODEM","CBE"]
def expectedList = ["CABLE_CARD","SET_TOP_BOX","CABLE_MODEM","MTA","OTHER","IP_SET_TOP_BOX"]
match each actualList contains any expectedList

Basically, every value of the actualList should be any one of the expectedList value. But it is directly comparing the first value of the 2 lists. Kindly help me

Peter Thomas · Accepted Answer · 2022-08-18T18:51:35.097

I'm not sure I understand the question. But sometimes these crazy assertions are best done in JS:

* def actualList = ["CABLE_MODEM","SET_TOP_BOX","SET_TOP_BOX","CABLE_MODEM","CBE"]
* def expectedList = ["CABLE_CARD","SET_TOP_BOX","CABLE_MODEM","MTA","OTHER","IP_SET_TOP_BOX"]
* def unexpected = actualList.filter(x => !expectedList.includes(x))
* match unexpected == []

Please take the help of a friend who knows JS if the above is not clear.

EDIT: for completeness, here's the "karate style" way to solve this. For more complex custom checks, karate.match() can be used.

* def valid = function(x){ return expectedList.includes(x) }
* match each actualList == '#? valid(_)'

How to assert a list in which each value should be one the values of the expected list?

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