I have "react-dom-router v6.3.0" (strictly!) now and I couldn't understand how to handle browser's "back" button. For example I need to catch the event, so I could open warning modal that user leaves the page after clicking back. At least give me a direction, please.
I'm using Typescript 4.4.2.
The useBackListener:
import { useEffect, useContext } from "react";
import { NavigationType, UNSAFE_NavigationContext } from "react-router-dom";
import { History, Update } from "history";
const useBackListener = (callback: (...args: any) => void) => {
const navigator = useContext(UNSAFE_NavigationContext).navigator as History;
useEffect(() => {
const listener = ({ location, action }: Update) => {
console.log("listener", { location, action });
if (action === NavigationType.Pop) {
callback({ location, action });
}
};
const unlisten = navigator.listen(listener);
return unlisten;
}, [callback, navigator]);
};
Then usage:
useBackListener(({ location }) => {
if (isDirty) {
setOpenWarning(true)
} else navigate("go back")
})
How to open modal if form is dirty without redirecting after clicking browser's "back" button ? Also, is it possible to avoid @ts-ignore?