How to get date range at now to end of the month?

Question

I use datetime, i have:

delta = ((datetime.date.today() + datetime.timedelta(days=1)) - datetime.timedelta(???)).isoformat()

I need replace ??? with day to end of the month.

How to do it?

score 5 · Answer 1 · answered Sep 08 '11 at 11:31

5

To compute the end-of-the-current-month date, take the first of the current month, add 1 month and subtract 1 day. For example, for 28 September, you'll end up with

1 September + 1 month = 1 October
1 October - 1 day = 30 September.

answered Sep 08 '11 at 11:31

Aleks G

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But hot to do it using datetime? I have datetime format data in variable – Nips Sep 08 '11 at 12:19

score 3 · Accepted Answer · edited May 06 '14 at 12:00

3

import datetime

d = datetime.date(2013,12,8)

last_day = datetime.date(d.year, (d.month+1)%12, 1) - datetime.timedelta(1,0,0)

edited May 06 '14 at 12:00

Stefano Altieri

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answered Sep 08 '11 at 13:50

rocksportrocker

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Author/editor didn't notice this breaks for November: if d.month == 11, then (11 + 1) % 12 = 0, but the month value must be between 1 and 12. Don't think there's a nice way around this other than an ugly if-branch or obfuscated oneliner. – trujello Jul 14 '21 at 23:30

score 0 · Answer 3 · edited May 23 '17 at 12:20

0

To properly deal with dates around a new year, I found dateutil.relativedelta to be a better alternative.

See also How to increment datetime month in python.

import datetime
from dateutil.relativedelta import relativedelta

d = datetime.date(2013,12,8)

last_day = datetime.date(d.year, d.month, 1)+relativedelta(months=1, days=-1)

edited May 23 '17 at 12:20

Community

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answered May 06 '14 at 14:19

Salomon Tetelepta

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How to get date range at now to end of the month?

3 Answers3