PHP - JSON response

Asked Aug 25 '22 at 17:49

Active Aug 25 '22 at 17:58

Viewed 15 times

I am getting the following back from an API:

{"status": 200, "msg": "Successfully authenticated", "data": {"token": xxxxx", "token_expiration_datetime": "2022-08-26T17:38:11.515215"}}

And I need to get the token response in a variable to post else where. when I use: 'json_decode $data' I am getting the following back:

200Successfully authenticatedArray

The way I have done this previously is to use $output_decode=json_decode($data, true) and then extract($output_decode, EXTR_PREFIX_SAME, "clash");

It's probably something really simple but I am very rusty and trying to finish up so I can go on vacation! Any ideas.

If I use var_dump($output_decode); I am getting the following:

array(3) {
  ["status"]=>
  int(200)
  ["msg"]=>
  string(26) "Successfully authenticated"
  ["data"]=>
  array(2) {
    ["token"]=>
    string(128) "xxxxx"
    ["token_expiration_datetime"]=>
    string(26) "2022-08-26T17:56:18.857176"
  }
}

So I guess the query is how to I get the token from the second array back to a variable?

edited Aug 25 '22 at 17:58

asked Aug 25 '22 at 17:49

saxopete

`$output_decode['status']`. – Barmar Aug 25 '22 at 17:51
You get `Array` if you try to echo an array, like the nested `data` value. Use `var_dump()` instead of `echo`. – Barmar Aug 25 '22 at 17:53
Just added clarification to the question – saxopete Aug 25 '22 at 17:58
`$output_decode['data']['token']`. This is basic PHP. – Barmar Aug 25 '22 at 18:00
Thank you - it's been a long day and just going deeper and deeper down the rabbit hole! – saxopete Aug 25 '22 at 18:05

PHP - JSON response

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