Async Await Gives Syntax Error Even when code Is correct

Question

I have very simple code as below .

Function ls has async keyword and it returns Promise.

But , calling const val = await ls() gives below error.

SyntaxError: await is only valid in async functions and the top level bodies of modules

Can anybody pleasse help me why this error is coming as :

The function ls has async keyword
It also returns a Promise

Further more , using then clause like below , it works fine

ls().then(val => console.log(val)).catch(e => e)

But below code doesn't work

   async function ls() {
        return new Promise((resolve) => {
            resolve('Print Output !!')
        });
    }
    
    const val = await ls()
    console.log(val)

Error is self-descriptive that *SyntaxError: await is only valid in async functions and the top level bodies of modules* — DecPK, Aug 26 '22 at 04:59
Is the code `await ls()` inside an async function or at the top level of a module? No, it's not. Therefore, it's not valid. Therefore, the code is not correct. Therefore the error message you saw was very precise and accurate in describing what the error is. — VLAZ, Aug 26 '22 at 05:10

score 2 · Accepted Answer · answered Aug 26 '22 at 04:57

async function ls() {
    return new Promise((resolve) => {
        resolve('Print Output !!')
    });
}

// Way 1
async function test() { //function created for "await ls()"
    const val = await ls(); //this await requires async
    console.log("Way 1 " + val)
}
test();

// Way 2
(async function() {
    const val = await ls();
    console.log("Way 2 " + val)
})();

Async Await Gives Syntax Error Even when code Is correct

1 Answers1