This is a program that takes input as number and print the digit in an array as output

Question

number = int(input())
numList = [int(digit) for digit in str(number)]
print(numList)

In this code when i enter the number 010 the output is being [1, 0] instead of [0, 1, 0]. please help Can i also get suggestion on how to add 0 to list if input number begins with 0

Don't convert the `input()` to an `int`. Use `number = input()` then `numList = [ ... in number]`. — quamrana, Sep 01 '22 at 13:23
Does this answer your question? [How to split integer input in python?](https://stackoverflow.com/questions/49064817/how-to-split-integer-input-in-python) — Gino Mempin, Sep 01 '22 at 13:24

Prashant Kumar · Answer 1 · 2022-09-01T13:30:04.550

2

Try this :

number = input()
numList = [int(digit) for digit in number]
print(numList)

Explanation:

Whenever you take a user input, it is considered as string. So you input 0110 will be saved in number variable as string "0110".

Now you can iterate over the string characters and convert them to integers in list comprehension.

edited Sep 01 '22 at 13:30

answered Sep 01 '22 at 13:23

Prashant Kumar

2,057
2
9
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Or with a functional approach: `num_list = list(map(int, input()))` – Matthias Sep 01 '22 at 13:47
Yes sure. But comprehension and map usage might become a little tricky to understand at this point. – Prashant Kumar Sep 01 '22 at 13:50

Sezgin Karagülle · Answer 2 · 2022-09-01T13:28:58.513

-2

numberList = []
number = input("Enter the number: ")
for xx in number:
    numberList.append(int(xx))


print("LİST: ",numberList)

edited Sep 01 '22 at 13:28

answered Sep 01 '22 at 13:28

Sezgin Karagülle

1
1

This is a program that takes input as number and print the digit in an array as output

2 Answers2