Strptime How to convert to a datetime object

Question

Hello i'm trying to obtain an datetime object with "T" and "Z" so i can pass it to youtube API. After i convert it the STRPTIME can't match the format and i don't understand why, i have tried all day to get rid of this.

actual_time = datetime.utcnow()
    actual_time = actual_time.isoformat("T") +"Z"
    actual_time = datetime.strptime(actual_time, '%y-%m-%dT%H:%M:%S.%f%z')
    print(actual_time)

This is the error i get:

raise ValueError("time data %r does not match format %r" %

time data '2022-09-03T09:52:49.464164Z' does not match format '%y-%m-%dT%H:%M:%S.%f%z'

`datetime.datetime(2022, 9, 3, 10, 7, 8, 681996, tzinfo=tzutc())` is this form acceptable? — Mehmaam, Sep 03 '22 at 10:12
Does this answer your question? [How do I parse an ISO 8601-formatted date?](https://stackoverflow.com/questions/127803/how-do-i-parse-an-iso-8601-formatted-date) — FObersteiner, Sep 03 '22 at 14:28

score 1 · Answer 1 · answered Sep 03 '22 at 10:16

from dateutil library import parser then convert into parser.parser()

Code:

from dateutil import parser
from datetime import datetime
actual_time = datetime.utcnow()
actual_time = actual_time.isoformat("T") +"Z"
print("actual time",actual_time)
parser.parse(actual_time)

Output:

actual time 2022-09-03T10:09:36.784768Z
datetime.datetime(2022, 9, 3, 10, 9, 36, 784768, tzinfo=tzutc())

Strptime How to convert to a datetime object

1 Answers1