sort a list in numerical order that has letter(s)

Asked Sep 05 '22 at 19:33

Active Sep 05 '22 at 19:33

Viewed 25 times

list = ["a9", "a11", "a6", "a2", "a4", "a12", "a10", "a15", "a17"]

From this list I would want to sort the list so that the numbers behind 'a' is in numerical order. Is there a simple way to do this?

output wanted:

list = ["a2", "a4", "a6", "a9", "a10", "a11", "a12", "a15", "a17"]

asked Sep 05 '22 at 19:33

ApplesAreFruits

2

Use `key=lambda x: int(x.lstrip('a'))`? – ShadowRanger Sep 05 '22 at 19:35
1

list.sort(key=lambda x: int(x[1:])) for any first character – Stackerexp Sep 05 '22 at 19:37
Thank you @Stackerexp the code works now – ApplesAreFruits Sep 05 '22 at 19:39
1

Interesting to generalize this *puzzle* - if List has *b01, b11, b02* ...? – Daniel Hao Sep 05 '22 at 21:37

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