Macro Take String with comma?

Asked Sep 06 '22 at 06:55

Active Sep 06 '22 at 06:57

Viewed 14 times

So if I have a macro like this (simplified example)

#define LOG(TYPE) LOG_STUFF(TYPE, #TYPE);

I want to use it like this

LOG(TMap<int32, int32>);

So #TYPE should become "TMap<int32, int32>" but instead it becomes "TMap<int32" and comma is taken as next parameter. Can I fix this or do I have to pass string manually?

edited Sep 06 '22 at 06:57

asked Sep 06 '22 at 06:55

M.kazem Akhgary

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You mean comma, not colon – Alan Birtles Sep 06 '22 at 06:56
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`#define LOG(...) LOG_STUFF(__VA_ARGS__, #__VA_ARGS__);` – HolyBlackCat Sep 06 '22 at 06:57
Macros are generally discouraged in modern C++. They have many drawbacks compared to functions, and you have discovered one of them. – Some programmer dude Sep 06 '22 at 06:57
Yeah, I was just trying to do some testing and log stuff. definitely not production code. @Someprogrammerdude – M.kazem Akhgary Sep 06 '22 at 06:58
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@M.kazemAkhgary Add extra `()`, like this `LOG((TMap));` – john Sep 06 '22 at 07:07
@john nice trick! It works for the string part, it doesn't for other part that wasn't included in my question :) in my case `sizeof(TYPE)` – M.kazem Akhgary Sep 06 '22 at 07:15

Macro Take String with comma?

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