Format date from String to LocalDate

Question

I have a problem parsing a String to LocalDate.
According to similar questions on Stackoverflow and documentation I am using the correct values dd (day of the month), MM (month of the year) and yyyy (year).

My String

String mydate = "18.10.2022 07:50:18";

My parsing test code

System.out.println(
    LocalDate.parse(testPasswordExp)
             .format(DateTimeFormatter.ofPattern("dd.MM.yyyy HH:mm:ss")
    )
);

Error:

Caused by: java.lang.RuntimeException:
java.time.format.DateTimeParseException:
Text '18.10.2022 07:50:18' could not be parsed at index 0

This looks like you need a `LocalDateTime` instead of a `LocalDate`. — MC Emperor, Sep 06 '22 at 08:08
Does this answer your question? [String to LocalDate](https://stackoverflow.com/questions/8746084/string-to-localdate) — abdo Salm, Sep 06 '22 at 09:26

deHaar · Answer 1 · 2022-09-06T09:06:42.120

The main problem of your code example is that you first parse the String to a LocalDate without the use of a suitable DateTimeFormatter and then format() it with a DateTimeFormatter that tries to format hour of day, minute of hour and second of minute which just aren't there in a LocalDate.

You can parse this String to a LocalDate directly, but better parse it to a LocalDateTime because your String contains more than just information about

day of month
month of year
year

Your myDate (and probably the testPasswordExp, too) has a time of day. You can get a LocalDate as the final result that way, too, because a LocalDateTime can be narrowed down toLocalDate().

A possible way:

public static void main(String[] args) {
    // example datetime
    String testPasswordExp = "18.10.2022 07:50:18";
    
    System.out.println(
        LocalDateTime   // use a LocalDateTime and…
            .parse(     // … parse …
                testPasswordExp,    // … the datetime using a specific formatter,
                DateTimeFormatter.ofPattern("dd.MM.uuuu HH:mm:ss")
            ).toLocalDate() // then extract the LocalDate
    );
}

Output:

2022-10-18

Thank you, I'm parsing it because i have to comapre two dates, but now i know i have to separately comapre date and time. — Tacoo, Sep 06 '22 at 08:13
If you want, you may parse it into a `LocalDate`, but it’s not advisable. Better to go through a `LocalDateTime` as shown in the answer. And if right for your situation, you can compare two `LocalDateTime` objects using their `isBefore` or `isAfter` method -- provided that both are in the same time zone. — Ole V.V., Sep 06 '22 at 08:59

score 1 · Accepted Answer · edited Sep 07 '22 at 07:53

1

You don't use the specified format for parsing, you use it to format the parsed date.

LocalDate.parse(mydate)

… uses the default ISO_LOCAL_DATE format. You are looking for this overload:

LocalDate.parse(mydate, DateTimeFormatter.ofPattern("dd.MM.yyyy HH:mm:ss"))

This method uses the specified format for parsing string to date. See this code run at Ideone.com.

Note that you are using LocalDate, meaning it will throw away the time part, keeping only the date after parsing. You probably meant to use LocalDateTime.

edited Sep 07 '22 at 07:53

Basil Bourque

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answered Sep 06 '22 at 07:56

Chaosfire

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@deHaar No it won't, i tested it before posting the answer. – Chaosfire Sep 06 '22 at 08:14
2

@deHaar the code in this answer works for me (JDK 17 on Windows 10), i.e. no `DateTimeParseException` – Abra Sep 06 '22 at 08:18
OK, I tested it with a later version and that indeed worked. – deHaar Sep 06 '22 at 08:27

neha · Answer 3 · 2022-09-06T09:44:03.673

0

You can use

    String mydate = "18.10.2022 07:50:18";


    LocalDate ld = LocalDate.parse(mydate, DateTimeFormatter.ofPattern("dd.MM.yyyy HH:mm:ss"));

    System.out.println(ld.toString());

edited Sep 06 '22 at 09:44

answered Sep 06 '22 at 09:30

neha

62
5

This Answer repeats the content of the earlier [Answer by Chaosfire](https://stackoverflow.com/a/73618585/642706). – Basil Bourque Sep 06 '22 at 16:55

Format date from String to LocalDate

3 Answers3